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Monday, January 15, 2024

Light full solution with explanation and image formations for class 7 CBSE chapter 15

 


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L I G H T S

By Farrukh Asif

 

Ø Light travels in straight lines.

Ø Speed of Light

Ø Waves of Light

Ø Colours of Light

Ø How Light Travels

Ø To Summarise

 

LIGHT AND ITS PROPERTIES:

Light from the Sun is a natural example of white light.

Mixing colours of light is an example of additive colour mixing. Red appears red to us because right wavelengths of light are sent towards our eyes. The same is true for all of the other colours. White is created by sending out all of the wavelength of light. So what about black? In additive colour mixing, black is the absence of light. In other words, no wavelength of light is sent out. We perceive this lack of light as black!

Sometimes white light from the Sun is split apart so that we can see the colours that make it up. A good example of this are rainbows. Small water droplets split the waves of light so that we can see each.

How Light Travels

The final important property of light to remember is that light always travels in a straight line. We get shadows when light is blocked by an object. Light can pass through some but not all objects. We call objects and materials that light can pass through transparent. We can objects and materials that light cannot pass through opaque. We call objects that let some, but not all light pass through translucent.


To Summarise

  • Light travels very fast - at the speed of 299 792 458 m / s in fact!
  • Light travels as waves.
  • Light travels in straight lines.

Can you remember the order of the colours of a rainbow?

Some people use the phrase ROY G BIV to remember it. These are the first letters of the colours red, orange, yellow, green, blue, indigo, and violet.

We can also split light using a prism.

Waves of Light



Light has the properties of waves. Like ocean waves, light waves have crests and troughs.

The distance between one crest and the next, which is the same as the distance between one trough and the next, is called the wavelength.

The frequency of a wave is the number of crests (or troughs) that pass a point in one second. The wavelength multiplied by the frequency equals the speed at which the wave travels.

These different colours of light have different wavelengths and frequencies. Red light has the longest wavelength, and the lowest frequency of the visible spectrum. Violet has the shortest wavelength, and the highest frequency of the visible spectrum.

Speed of Light:

          The speed of light is : 299 792 458 m / s

Colours of Light:

You will remember from art class that the primary colours are red, yellow and blue.

You can mix these to form the secondary colours orange, green and purple.

Black absorbs all of the colours of light and does not reflect any colours. We perceive this lack of light as black!

The Primary colors of th Light are redgreen and blue.

The Secondary colours of light are cyanmagenta and yellow.

·        Cyan is made by combining blue and green.

·        Magenta is made by combining blue and red.

·        Yellow is made by combining green and red.

Computer screens and TV screens use these colours of light to make all of the colours that you see.

                               Primary and secondary colours of light

  Mixing colours of light is an example of additive colour mixing. Red appears red to us because right wavelengths of light are sent towards our eyes. The same is true for all of the other colours. White is created by sending out all of the wavelength of light.

What do these experiences suggest?

LIGHT TRAVELS ALONG A STRAIGHT LINE:

When the boy see at a lighted candle first through a straight pipe and then through a bent pipe (Fig. 15.2).

Why was Boy not able to see the candle flame through a bent pipe?

This activity showed that light travels along straight lines.

How can we change the path of light? Do you know, what happens when light falls on a polished or shiny surface?

REFLECTION OF LIGHT:

One way to change the direction of light is to let it fall on a shiny surface. For example, a shining stainless steel plate or a shining steel spoon can change the direction of light. The surface of the water can also act like a mirror and change the path of light.

Have you ever seen the reflection of trees or buildings in water?

Any polished or shiny surface can act as a mirror. What happens when light falls on a mirror? You have learnt in Class VI that a mirror changes the direction of light that falls on it. This change of direction by a mirror is called reflection of light. Place a lighted candle in front of a plane mirror. Try to see the flame of the candle in the mirror. It appears as if a similar candle is placed behind the mirror. The candle, which appears behind the mirror, is the image of the candle formed by the mirror (Fig. 15.6). The candle itself is the object. Now move the candle to different positions in front of the mirror. Observe the image in each case.

Was the image upright in each case? Did the flame appear on top of the candle as in the object? Such an image is called erect. An image formed by a plane mirror is erect and of the same size as the object. Now place a vertical screen behind the mirror. Try to obtain the image of the candle on this screen.

Can you get the image on the screen?

Now place the screen in front of the mirror.

Can you get the image on the screen now?



You will find that the image of the candle cannot be obtained on the screen in either case. What about the distance of the image from the mirror?

Let us perform another activity.

Take a chessboard. If a chessboard is not available, draw on a chart paper 64 (8×8) squares of equal size. Draw a thick line in the middle of the paper. Fix a plane mirror vertically on this line. Place any small object, such as a pencil sharpener, at the boundary of the third square counting from the mirror (Fig. 15.7). Note the position of the image. Now shift the object to the boundary of the fourth square. Again note the position of the image. Did you find any relation between the distance of the image from the mirror and that of the object in front of it?

You will find that the image is at the same distance behind the mirror as the object is in front of it. Now verify this by placing the object anywhere on the chart paper.

SPHERICAL MIRRORS:

The curved shining surface of a spoon acts as a mirror. The most common example of a curved mirror is a spherical mirror. If the reflecting surface of a spherical mirror is concave, it is called a concave mirror. If the reflecting surface is convex, then it is a convex mirror/


Take a concave mirror. Hold it facing the Sun. Try to get the light reflected by the mirror on a sheet of paper. Adjust the distance of the paper until you get a sharp bright spot on it

(Fig. 15.14). Hold the mirror and the sheet of paper steady for a few minutes.

Does the paper start burning?

This bright spot is, in fact, the image of the Sun. Notice that this image is formed on a screen. An image formed on a screen is called a real image. Recollect that in Activity 15.2 the image formed by a plane mirror could not be obtained on a screen. Such an image is called a virtual image. Now let us try to obtain on the screen the image of a candle flame formed by a concave mirror.

IMAGES FORMED BY LENSES:

You might have seen a magnifying glass. It is used to read very small print (Fig. 15.21). You might have also used it to observe the body parts of a cockroach or an earthworm. The magnifying glass is actually a type of a lens. Lenses are widely used in spectacles, telescopes and microscopes. Try to add a few more uses of lenses to this list. Get some lenses. Touch and feel them. Can you find some difference just by touching? Those lenses which feel thicker in the middle than at the edges are convex. Those which feel thinner in the middle than at the edges are concave lenses. Notice that the lenses are transparent and light can pass through them.



A convex lens converges (bends inward) the light generally falling on it [Fig. 15.24 (a)]. Therefore, it is called a converging lens. On the other hand, a concave lens diverges (bends outward) the light and is called a diverging lens [Fig. 15.24 (b)].


Important Terms for Image Formation

  • Ray Diagrams of Concave Mirror
  • Image Formation on Concave Mirror
  • Image Formation Tabular Data
  • Sign Conventions for Concave Mirror
  • Relation between Focal Length and Radius of Curvature
  • What is Mirror Equation?
  • Linear Magnification (m) Explanation
  • Solved Questions of Concave Mirror
  • Uses of Concave Mirrors

Important Terms for Image Formation:

1.   Pole: It is the centre of the reflecting surface of a spherical mirror. It lies on the surface of the mirror, and it is usually denoted by P.

2.   Centre of curvature: The centre of the sphere formed by the reflecting part of a spherical mirror is called the centre of curvature. It is generally denoted by C. This is not a part of the mirror, and it lies outside the reflecting surface of the mirror. In a concave mirror, it lies in front of the mirror.

3.   The radius of curvature: It is the radius of the sphere formed by the reflecting part of the sphere. It is represented by R.

4.   Principal axis: It is the straight line passing through the pole and centre of curvature of the spherical mirror. This is normal to the mirror at its pole.

5.   Principal focus: The incident rays coming parallel to the principal axis after reflection appear to converge to a common point on the principal axis, and this point is called the principal focus of a concave mirror. It is usually denoted by F.

6.   Focal length: It is the distance between the pole and the principal focus of the concave mirror. It is denoted by f.



Ray Diagrams of Concave Mirror:

Ray diagrams are necessary for understanding the formation of an image by a concave mirror. For constructing ray diagrams and for a better understanding of image formation, we should consider at least two incident rays coming from the object. The intersection of these two rays after reflection gives the position of the image of the object. For a concave mirror, any of the following four ray diagrams can be used for locating the image formed:

a) A ray parallel to the principal axis, after reflection, will pass through the principal focus of a concave mirror.



b) A ray which is passing through the principal focus of a concave mirror, after reflection, will emerge parallel to the principal axis.



 c) A ray passing through the centre of curvature of a concave mirror, after reflection, is reflected along the same path. The light rays come back along the same path because the incident rays fall on the mirror along the normal to the reflecting surface.



 d) A ray incident obliquely to the principal axis, towards the point P (pole of the mirror), on the concave mirror, is reflected obliquely. The incident and reflected rays follow the laws of reflection at point P, making equal angles with the principal axis.

Image Formation on Concave Mirror:

Rays emerging from a point meet at another point after reflection, and this point is called the image of the first point. The image is real if the rays converge to the point, and it is virtual if the rays do not meet it, but appear to diverge from a point when the rays are produced backwards. During image formation, we assume that the rays are paraxial, i.e., they are incident at points close to the pole P of the mirror and make small angles with the principal axis. For a concave mirror, we consider six positions of the object before the mirror.

Also Read: Difference between Convex and Concave Mirror

1. When the object is placed at infinity

2. When the object is placed beyond C (centre of curvature)

3. When the object is placed at C

4. When the object is placed between C and F (principal focus)

5. When the object is placed at F

6. When the object is placed between F and P (pole)

When the Object Is at Infinity:

In this condition, we consider two rays parallel to the principal axis originating from the object. These rays, after reflection, converge and form an image at F, the principal focus of the mirror, in front of the mirror. The image thus formed is highly diminished, point size, real and inverted.

The Object Is Placed Beyond C:



In this situation, we consider two different rays emerging from the object. One is parallel to the principal axis, and the other is directed towards the centre of curvature of the mirror. These rays, after reflection, form an image between the centre of curvature (C) and the focus (F). The image thus formed is diminished, real and inverted.

 The Object Is Placed at C:



Here, the two rays emerging from the object are one parallel to the principal axis and the other passing through the focus of the mirror. These rays, after reflection, form an image at point C. The image formed has the same size as that of the object, and it is real and inverted.

 The Object Is Placed between C and F:



Here, the two rays considered are one parallel to the principal axis and the other passing through the principal focus of the concave mirror. The image is formed beyond C. The image is larger compared to the size of the object, and it is real and inverted.

The Object Is Placed at F:



The rays considered here are one parallel to the principal axis and the other passing through the centre of curvature of the mirror. This results in the formation of a highly enlarged image which is real and inverted at infinity.

 

The Object Is Placed between F and P:



The rays considered here are one going parallel to the principal axis and the other passing through the centre of curvature of the mirror. The image formed here is virtual and erect, and it is larger than the object.

 Image Formation Tabular Data

Position of the Object

Position of the Image

Size of the Image

Nature of the Image

At infinity

At focus, F

Highly diminished and pointed in size

Inverted and real

Beyond C

Between F and C

Diminished

Inverted and real

At C

At C

Same size

Inverted and real

Between C and F

Beyond C

Enlarged

Inverted and real

At F

At infinity

Highly enlarged

Inverted and real

Between F and P

Behind the mirror

Enlarged

Erect and virtual

Concave Mirror Sign Conventions:





For deriving the relevant formulas for reflection by spherical mirrors, there is a standard sign convention for measuring distances. The normally used convention is the Cartesian sign convention. According to this convention, all the distances are measured from the pole of the mirror, i.e., the pole (P) of the mirror is assumed as the origin. The principal axis of the mirror is taken as the x-axis of the coordinate system. The conventions are as given below:

  • The object is always placed on the left side of the mirror. This means that the light from the object falls on the mirror from the left-hand side.
  • All the distances which are parallel to the principal axis are measured from the pole of the mirror.
  • All the distances measured towards the right of the origin (along + x-axis) are taken as positive and while those measured to the left of the origin (along – x-axis) are taken as negative, or the distances measured in the same direction as that of the incident light are taken as positive and those measured in the direction opposite to the direction of incident light are taken as negative.
  • Distances measured perpendicular to and above the principal axis of the mirrors are taken as positive.
  • Distances measured perpendicular to and below the principal axis of the mirrors are taken as negative.

Relation between Radius of Curvature and Focal Length



Consider a ray parallel to the principal axis striking the concave mirror at a point M on its reflecting surface. Then CM will be perpendicular to the mirror at point M. Let θ be the angle of incidence, and MD be the perpendicular from M to the principal axis.

 

Then from the figure,

MCP = θ and MFP = 2θ

Now,

Tanθ = MD / CD and tan2θ = MD / FD

For small values of θ, which is true for paraxial rays, tan θ ≈ θ and tan 2θ ≈ 2θ

Therefore, MD / FD = 2 X MD / CD or FD = CD / 2

Now, FD = f and CD = R, therefore the above equations become

f = R / 2

This is from the assumption that for small values of θ point, D is very close to point P.

 

Mirror Equation:



 The figure shows two rays emerging from the object. These rays, after reflection, form an image A’B’. From the geometry of ray diagrams, the two right-angled triangles ABF and MPF are similar. This is because, for paraxial rays, the line MP can be considered to be a straight line perpendicular to CP. Therefore,

BA / PM = BF / FP or BA / BA = BF / FP (Since PM = AB) …… (1)

Since APB = A’PB’, the right-angled triangles A’B’P and ABP are also similar,

BA / BA = BP / BP ……………… (2)

Comparing the equations (1) and (2), we get,

BF / FP = BP – FP / FP = BP / BP

This is the relationship involving the magnitude of distances.

In a spherical mirror, the distance of the object from its pole is called the object distance (u) and the distance of the image from the pole is called the image distance (v). As mentioned earlier, the distance of the principal focus from the pole is called the focal length (f).

Substituting u, v, and f by following the sign convention, we get,

-v + f / -f = -v / -u or v – f / f = v / u or 1 / u + 1 / v = 1 / f

This equation is known as the mirror equation. This is valid for both convex and concave mirrors.

Linear Magnification (m)

Linear magnification (m) is the ratio of the height of the image (h’) to the height of the object (h).

m = h / h

h’ and h are given a positive or negative value as per the Cartesian sign convention.

In triangles A’B’P and ABP, we have

BA / BA = BP / BP

By applying sign convention, we get

m = h / h = – v / u

A negative sign for the value of magnification indicates that the image is real, and a positive sign indicates that the image is virtual.

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Concave Mirror Solved Questions

1. An object is found to be 5 cm in front of a concave mirror with a radius of curvature of 15 cm. Determine the position, nature, and magnification of the image in each case.

Answer:

focal length, f = =15/2 cm = 7.5 cm

u = -5 cm

Applying the mirror formula, we get,

1 / V + I / -5 = 1 / -7.5

1 / V = I / -7.5 + 1 / 5 = 1 / 15

Therefore, v =15 cm

Thus, a virtual and erect image is formed 15 cm behind the mirror.

Magnification, m = – v / u = 15 / -5 = 3

Thus, the image formed is virtual, erect and magnified by a factor of 3.

2. An object, 4 cm in size, is placed at 25 cm in front of a concave mirror of focal length 15 cm. At what distance from the mirror should a screen be placed to obtain a sharp image? Determine the nature and the size of the image.

Answer:

Object size, h = + 4 cm

Object distance, u = – 25 cm

Focal length, f = –15 cm

By using the mirror equation,

1 / V = I / -15 – 1 / -25 = – 1 / 15 + 1 / 25

1 / V = -5 + 3 / 75 = 2 / 75

i.e. v = – 38.5 cm

To get the image on the screen, the screen should be placed at a distance of 38.5 cm from the mirror.

Magnification, m = h / h = – v / u

Therefore,

h = – vh / u = (-38.5 x 4) / -25 = 6.16

Height of the image, h’ = 6 cm, so the image formed is real, inverted and enlarged.

Uses of Concave Mirrors:

Concave mirrors are used in many instances. Some of the common ones are given below.

  • Torches, searchlights and vehicle headlights use concave mirrors to get powerful parallel beams of light.
  • Shaving mirrors used are usually concave mirrors to get a magnified image of the face.
  • To see large images of the teeth of patients, dentists use concave mirrors.
  • Concave mirrors are also used in reflecting telescopes.
  • Concave mirrors are used to form optical cavities, which are important in the construction of lasers.
  • For concentrating sunlight to produce heat in solar furnaces, large concave mirrors are used.
  • Concave mirrors are used as the mirror landing aid system of modern aircraft carriers.


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Solutions of Science Chapter 15 Light

 

1. Fill in the blanks.

(a) An image that cannot be obtained on a screen is called a ____________.

(b) Image formed by a convex __________ is always virtual and smaller in size.

(c) An image formed by a __________ mirror is always of the same size as that of the object.

(d) An image which can be obtained on a screen is called a _________ image.

(e) An image formed by a concave ___________ cannot be obtained on a screen.

Answer:

 (a) An image that cannot be obtained on a screen is called a virtual image.

(b) Image formed by a convex mirror is always virtual and smaller in size.

(c) An image formed by a plane mirror is always of the same size as that of the object.

          (d) An image which can be obtained on a screen is called a real image.

(e) An image formed by a concave lens cannot be obtained on a screen.

 

2. Mark ‘T’ if the statement is true and ‘F’ if it is false.

(a) We can obtain an enlarged and erect image by a convex mirror. (T/F)

(b) A concave lens always form a virtual image. (T/F)

(c) We can obtain a real, enlarged and inverted image by a concave mirror. (T/F)

(d) A real image cannot be obtained on a screen. (T/F)

(e) A concave mirror always forms a real image. (T/F)

Answer:

a) False

b) True

c) True

d) False

e) False

 

3. Match the items given in Column I with one or more items in Column II.

Column-I

Column-II

(a) A plane mirror

(i) Used as a magnifying glass.

(b) A convex mirror

(ii) Can form images of objects spread over a large area.

(c) A convex lens

(iii) Used by dentists to see an enlarged image of teeth.

(d) A concave mirror

(iv) The image is always inverted and magnified.

(e) A concave lens

(v) The image is erect and of the same size as the object.

(vi) The image is erect and smaller in size than the object.

 

Answer:

Column-I

Column-II

(a) A plane mirror

(v) The image is erect and of the same size as the object.

(b) A convex mirror

(ii) Can form an image of objects spread over a large area.

(c) A convex lens

(i) Used as a magnifying glass.

(d) A concave mirror

(iii) Used by dentists to see an enlarged image of teeth.

(e) A concave lens

(vi) The image is erect and smaller in size than the object.

 

 

4. State the characteristics of the image formed by a plane mirror.

Answer:

Characteristics of the image formed by a Plane Mirror are as follows:

·        Image distance and object distance are equal.

·        The size of the object and image are equal.

·        The image formed is erect and virtual.

·        Images are laterally inverted.

 

5. Find out the letters of the English alphabet or any other language known to you in which the image formed in a plane mirror appears exactly like the letter itself. Discuss your findings.

Answer:

A, H, I, M, O, T, U, V, W, X, and Y alphabets form images in a plane mirror exactly like the letter itself because these alphabets are laterally symmetric.

 

6. What is a virtual image? Give one situation where a virtual image is formed.

Answer:

The image that cannot be obtained on a screen is called a virtual image. The image formed by a plane mirror is virtual.

 7. State two differences between a convex and a concave lens.

Answer:

Convex Lens

Concave Lens

Thick in the middle and thin at the edge.

Thin in the middle and thick at the edge.

The image formed is real or virtual.

The image formed is virtual.

 

8. Give one use each of a concave and a convex mirror.

Answer:

·        Concave mirrors are used in the headlights of cars and scooters.

·        Convex mirrors are used as side-view mirrors in vehicles.

 

9. Which type of mirror can form a real image?

Solution:

·        The concave mirror can form a real image.

 

10. Which type of lens always forms a virtual image?

Answer:

·        A concave lens forms a virtual image.

Choose the correct option in questions 11–13.

11. A virtual image larger than the object can be produced by a

(i) concave lens (ii) concave mirror

(iii) convex mirror (iv) plane mirror

Answer:

ü The correct answer is option (ii) concave mirror.

12. David is observing his image in a plane mirror. The distance between the mirror and his image is 4 m. If he moves 1 m towards the mirror, then the distance between David and his image will be

(i) 3 m (ii) 5 m

(iii) 6 m (iv) 8 m

Answer:

ü The answer is option (iii) 6 m

13. The rearview mirror of a car is a plane mirror. A driver is reversing his car at a speed of 2 m/s. The driver sees in his rearview mirror the image of a truck parked behind his car. The speed at which the image of the truck appears to approach the driver will be

(i) 1 m/s (ii) 2 m/s

(iii) 4 m/s (iv) 8 m/s

Answer:

ü The correct answer is option (iii) 4 m/s.

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